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Quantities

Paving units & bedding

N=⌈A×1 000 000(L+j)(W+j)(1+w100)⌉Vb=Ad1000
where
N
pavers to order
A
area (m²)
L
paver length (mm)
j
joint (mm)
W
paver width (mm)
w
waste (%)
Vb
bedding volume (m³)
d
bed depth (mm)
Explain this equation

This estimates how many rectangular paving units to order for an area, and the volume of bedding material under them.

A is the area in m². L and W are the paver length and width and j is the joint, all in mm. N is the number of pavers including the waste w. d is the bed depth in mm and V_b is the bedding volume in m³.

Each paver with a joint on two sides covers (L + j)(W + j) mm². There are 1 000 000 mm² in a square metre, so that gives pavers per m²; multiplying by area and (1 + w/100) gives the order, and the ⌈ ⌉ brackets round up. The bed is area times depth, divided by 1000 to turn mm into m.

A 200 × 100 mm paver with a 5 mm joint gives about 46.5 per m². Twenty square metres with 5% waste is 976 pavers. A 40 mm bed over 20 m² is 0.8 m³.

Watch out: cuts, laying patterns and compaction all change the real quantities.

Estimate rectangular pavers and a uniform bed.

m²
mm
mm
mm
%
mm

Enter your values to see the result.

Good to know

Use the specified laying orientation, joints and bedding system. Cuts, pattern and compaction can alter actual quantities.

Sources

  • Geometry / arithmetic

Estimates are not design approval or British Standards compliance checks. Structural arch, retaining-wall, wind, foundation, lintel and masonry-capacity design are not performed. Use the project engineer’s specification.