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Setting out

Count for a maximum clear gap

n=⌈W−gmaxb+gmax⌉g=W−nbn+1
where
n
member count
W
clear opening (mm)
gmax
specified maximum gap (mm)
b
member width (mm)
g
actual gap (mm)
Explain this equation

Finds the fewest members needed so that no clear gap in an opening exceeds a specified maximum, then the actual equal gap.

W is the clear opening, b the member width and gmax the largest gap allowed, all in millimetres. n is the number of members, and g the actual gap.

n members need n + 1 gaps, so nb + (n + 1)g = W. Setting g to gmax and solving for n gives (W − gmax)/(b + gmax). Rounding up with ⌈ ⌉ guarantees every gap is no wider than the limit. The second line then shares the leftover space equally.

A 1000 mm opening with 40 mm members and a 95 mm maximum needs 7 members, giving 90 mm gaps.

Watch out: the maximum gap must come from the design or regulations. This calculator does not confirm compliance. It always uses at least one member.

Choose a whole member count so equal end and internal gaps do not exceed a specified limit.

mm
mm
mm

Enter your values to see the result.

Good to know

Maximum gap is supplied by the design. A gap calculation is not a guarding compliance check. Uses at least one member.

Sources

  • Geometry / arithmetic

This is a calculation aid, not a structural design or compliance certificate. Every default is an example, not a specification for your project.