Framing
Noggins between uniform members
- where
- noggin clear length (mm)
- centres (mm)
- member thickness (mm)
- noggin count
- bays
- rows
- total cut length (m)
Explain this equation
Works out the cut length, number and total length of noggins fitted between evenly spaced studs or joists.
c is the centre spacing of the members and t their thickness, both in millimetres. l is the clear gap a noggin must fill. b is the number of bays and r the number of noggin rows. N is the noggin count, and L the total cut length in metres.
Between two centres you lose half a member thickness at each side, which is one full thickness in total. So the clear length is c − t. Each bay gets one noggin per row. The /1000 turns the total from millimetres into metres.
400 mm centres with 47 mm studs gives 353 mm noggins. 9 bays and 2 rows need 18 pieces, about 6.35 m.
Watch out: there is no allowance for cutting waste, staggered rows or out-of-line members. Check a real gap before cutting a batch.
Calculate one noggin per bay per row between equal-thickness members.
Enter your values to see the result.
Good to know
Includes no trimming waste, stagger offsets or end rebates. Check the actual gap before cutting.
Sources
- Geometry / arithmetic
This is a calculation aid, not a structural design or compliance certificate. Every default is an example, not a specification for your project.